For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 10 N acts on a certain object, the acceleration of the object is 5 /ms2 . If the acceleration of the object becomes 6 /ms2 , what is the force

Answer:The force is 12 NStep-by-step explanation:* Lets explain how to solve the problem- Direct variation is a relationship between two variables that can  be expressed by an equation in which one variable is equal to a  constant times the other- If y ∝ x , then y = kx , where k is the constant of variation* Lets solve the problem- The force acting on the object varies directly with the object's   acceleration∵ The force is F in newtons and a is the acceleration is m/s²∴ F ∝ a∴ F = ka- To find k substitute F and a by the initial values of them∵ A force of 10 N acts on a certain object, the acceleration of the   object is 5 m/s²∵ F = 10 N when a = 5 m/s²∵ F = ka∴ 10 = k(5)- Divide both sides by 5∴ K = 2- Substitute the value of k in the equation∴ F = 2a- Lets find the force when the acceleration is 6 m/s²∵ a = 6 m/s²∴ F = 2(6) = 12* The force is 12 N