Circle all the ordered pairs (x,y) that are solutions to the equation 4x−y=10.(3,2) (2,3) (−1,−14) (0,0) (1,−6)(5,10) (0,−10) (3,4) (6,0) (4,−1)

Answer:Step-by-step explanation:given,equation  4 x−y=10-----(1)to be the solution of the ordered pair should satisfyputting(3,2)  4(3) - 2 = 10 hence (3,2)  is the solution of the equationputting(2,3)  4(2) - 3 = 5 hence (2,3)   is not the solution of the equationputting (−1,−14) 4(-1) - (-14) = 10 hence (−1,−14)   is  the solution of the equationputting (0,0) 4(0) - (0) = 0 hence (0,0)  is  not the solution of the equation.putting (1,−6) 4(1) - (-6) = 10 hence (1,−6) is   the solution of the equation.putting (5,10)4(5) - (10) = 10 hence (5,10) is   the solution of the equation.putting (0,−10)4(0) - (-10) = 10 hence (0,−10) is   the solution of the equation.putting (3,4)4(3) - (4) = 8 hence (3,4) is  not the solution of the equation.putting (6,0)4(6) - (0) = 24 hence (6,0) is  not the solution of the equation.putting (4,-1)4(4) - (-1) = 17 hence (4,−1) is  not the solution of the equation.now, circle order pairs is in the image attached below