We are standing on the top of a 1200 feet tall building and launch a small object upward. the object's vertical position, measured in feet, after t seconds is h(t)=−16t2+160t+1200. what is the highest point that the object reaches?

Answer:h = 1600 feet Step-by-step explanation:To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.Please see the attached image below, to find more information about the graphThe projectile formula is h(t) = a*t^2 + v*t + h0Where, v = initial vertical velocity of the object in feet per secondh0 = initial height of the object in feeth(t) = −16t^2 +160t + 1200If we look at the graph, we can find the point in which the height becomes maximum. For this problem,h = 1600 feet , at t = 5 seconds