Solve the following systems of equations r=2(s-t) ; 2t=3(s-r) ; r+t=2s-3.

Answer:r = 2s = 4t = 3Step-by-step explanation:Given:r = 2(s - t)  orr = 2s - 2t          .............(1)2t = 3( s - r)       ...............(2)r + t = 2s - 3         .............(3)substituting 1 in 3, we get2(s - t) + t = 2s - 3or2s - 2t + t = 2s - 3or-t = 2s - 3 - 2sort = 3substituting t in 3 we getr + 3 = 2s - 3 orr = 2s - 6substituting r and t in 2, we get2 × 3 = 3( s - (2s - 6)) or2 = s - 2s - 6or- 4 = -sors = 4substituting value of s and t in 1 , we getr = 2 ( 4 - 3 )orr = 2thus,r = 2s = 4t = 3