If a geometric sequence has a2 = 495 and a6 = 311, approximate the value of the common ratio ???? to four decimalplaces.

Answer:[tex]r = 0.8903 [/tex]Step-by-step explanation:given,a₂ = 495 a₆ = 311geometric  sequence formula                        [tex]a_n = ar^{n-1}[/tex]                        [tex]a_2 = ar^{2-1}[/tex]                        [tex]a_2 = ar [/tex]...................(1)                        [tex]a_6 = ar^{6-1}[/tex]                        [tex]a_6 = ar^5 [/tex]................(2)dividing equation (2) by (1)                      [tex]\dfrac{a_6}{a_2} = \dfrac{ar^5}{ar}[/tex]                      [tex]\dfrac{311}{495} = r^4[/tex]                      [tex]r^4 = 0.628 [/tex]                      [tex]r = 0.8903 [/tex]hence, the common ratio of the geometric sequence is [tex]r = 0.8903 [/tex]